Which of the following will not change the concentration of ammonia in the equilibrium?
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - x k J$

increase of pressure

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increase of temperature

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decrease of volume

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addition of catalyst

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Solution

The correct option is D addition of catalyst
Effect of catalyst is only to alter the speed of the reaction, it does not effect the equilibrium constant and concentration of reactant or product.

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Similar questions

Q. Formation of ammonia will be favorable in the following cases(s):

N_{2} (g) + 3 H_{2} (g) \to 2 N H_{3} (g)

Δ H < 0

Q. For the reaction

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), △ H = - 93.6 k J m o l^{- 1} .

The concentration of

H_{2}

at equilibrium will increase if

For the reaction $N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g), Δ H = - 93.6 k J m o l^{- 1}$ . The concentration of $H_{2}$ at equilibrium will increase if

N_{2} (g) + 3 H_{2} (g) ⇌ 2 {N H}_{3} (g) + h e a t

Given the reaction shown above, which change will not shift the equilibrium position for the reaction?

Q. What is the value of the equilibrium constant for the following reaction if the equilibrium concentrations of nitrogen, hydrogen, and ammonia are

1 M, 2 M,

and

15 M

respectively?

N_{2} (g) + 3 H_{2} (g) ⇋ 2 N H_{3} (g)

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Which of the following will not change the concentration of ammonia in the equilibrium?N2(g)+3H2(g)⇌2NH3(g);ΔH=−xkJ

The correct option is D addition of catalystEffect of catalyst is only to alter the speed of the reaction, it does not effect the equilibrium constant and concentration of reactant or product.

Which of the following will not change the concentration of ammonia in the equilibrium?
$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g); Δ H = - x k J$

The correct option is D addition of catalyst
Effect of catalyst is only to alter the speed of the reaction, it does not effect the equilibrium constant and concentration of reactant or product.