Which of the following will not give butanoic acid as one of the product?

C H_{3} C H_{2} C H_{2} B r M g ⟶ E t h e r (i) C O_{2} ⟶ (i i) H C l / H_{2} O

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C H_{3} C H_{2} C H_{2} B r N a C N (a q) ⟶ H^{+} / H_{2} O ⟶

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C H_{3} C H_{2} C H O + H C N H^{+} / H_{2} O ⟶

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C H_{3} C H_{2} C H_{2} C H = C H_{2} K M n O_{4} ⟶ H^{+} / H_{2} O

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Solution

The correct option is C $C H_{3} C H_{2} C H O + H C N H^{+} / H_{2} O ⟶$
Reaction:
$C H_{3} C H_{2} C H O + H C N H^{+} / H_{2} O ⟶ C H_{3} C H_{2} C H (O H) C N H_{2} O / H^{+} - ---- \to C H_{3} C H_{2} C H (O H) C O O H$

All other reaction gives butanoic acid $C H_{3} C H_{2} C H_{2} C O O H$ .

Option C is correct.

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