Which of the following will not give the chemical test for iron in aqueous solution

K_{2} F e_{2} S O_{4} .24 H_{2} O

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{(N H_{4})}_{2} S O_{4} . F e S O_{4} .6 H_{2} O

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K_{3} [F e F_{6}]

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F e_{4} [F e (C N)_{6}]_{3}

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Solution

The correct option is C $K_{3} [F e F_{6}]$
In $K_{3} [F e F_{6}]$ , all Fe ions are inside the complex which on ionisation in aqueous solution doesnot give Fe ions. So it doesnot give chemical test for iron.

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Similar questions

Q. Assertion :The complex

K_{3} [C r (C_{2} O_{4})_{3}]

when present in aqueous solution, will give test for

K^{+}

C r^{3 +}

and oxalate ions. Reason: The complex

K_{3} [C r (C_{2} O_{4})_{3}]

will dissociate completely in solution.

$F e S O_{4}$ solution mixed with ${(N H_{4})}_{2} S O_{4}$ solution in 1:1 molar ratio gives the test of $F e^{2 +}$ ion but $C u S O_{4}$ solution mixed wtih aqueous ammonia in 1:4 molar ratio does not give the test of $C u^{2 +}$ ion. Explain why?

Q. The ratio of the value of any colligative property for

K_{4} [F e {(C N)}_{6}]

solution to that of

{F e}_{4} {[F e {(C N)}_{6}]}_{3}

Q. Assertion :

{N H}_{2} - {N H}_{2}

gives Prussian blue colour during Lassaigne test (element detection test). Reason: NaCN gives Prussian blue colour of

{F e}_{4} {[F e ({C N}_{6})]}_{3}

with

F e {S o}_{4}, F e {C I}_{3}

In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of:

(a) Na₄[Fe(CN)₆] (b) Fe₄[Fe(CN)₆]₃ (c) Fe₂[Fe(CN)₆] (d) Fe₃[Fe(CN)₆]₄

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Which of the following will not give the chemical test for iron in aqueous solution

The correct option is C K3[FeF6]In K3[FeF6], all Fe ions are inside the complex which on ionisation in aqueous solution doesnot give Fe ions. So it doesnot give chemical test for iron.

The correct option is C $K_{3} [F e F_{6}]$
In $K_{3} [F e F_{6}]$ , all Fe ions are inside the complex which on ionisation in aqueous solution doesnot give Fe ions. So it doesnot give chemical test for iron.