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Question

Which of the following will shift the reaction PCl3(g)+Cl2(g)PCl5(g) to the left side:

A
addition of PCl3(g)
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B
increase in pressure
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C
decrease in pressure
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D
catalyst
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Solution

The correct option is B decrease in pressure
The given equilibrium :
PCl3(g)+Cl2(g)PCl5(g)
Since, no. of moles of gas are greater in reactant side. So, decrease of pressure will shift the reaction to left side.

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