Which of the following will show maximum -I effect?

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NO₂

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COOR

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C₆H₅

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Solution

The correct option is A

List of increasing -I effects:

$\oplus N$ $F_{3}$ $> \oplus N H_{3} > N O_{2} > C N > S O_{3} H > C H O > C O > C O O H > C O C l > C O O R > C O N H_{2} > F > C l > B r > I > O H > O R > N H_{2} > C \equiv C H > C_{6} H_{5} > C H = C H_{2} > H$

( $\to)$ Because of full or partial positive charge directly attached to carbon, the power of -I effect varies.

( $\to)$ $\oplus N$ $F_{3}$ has positive charge, therefore it will withdraw the electrons.

( $\to)$ In case of $N O_{2}$ , there are two oxygen which are more electronegative than N and withdraw electrons from N making it partially positive.

( $\to)$ COOR ( $\to)$ only one more electronegative oxygen attached to carbon directly.

Therefore,

$\oplus N F_{3} > N O_{2} > C O O R > C_{6} H_{5}$

Suggest Corrections

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