The correct options are
B OF C NO D B2The pressure of unpaired electrons leads to paramagnetic nature of substances.
Species having odd no. of electrons are definitely paramagnetic but the ones with even no. of electrons are not definitely diamagnetic thus requires work.
F2−18OF−17NO−15B2−10
⇒OF and NO are definitely paramagnetic
F2 & B2 are to be checked.
F2−18
Configuration:-σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2p2z,(π2p2xπ2p2y),(π∗2p2xπ∗2p2y)
⇒Diamagnetic
B2−10
Configuration:σ1s2,σ∗1s2,σ2s2,σ∗2s2,σ2p2z,(π2p1xπ2p1y)
⇒ Paramagnetic
Hence, Out of the given species, OF,NO and B2 are paramagnetic