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Bronsted Lowry Theory

Which of the ...

Question

Which of the given anions act as a strongest bronsted base?

C l O^{-}

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C l O_{3}^{-}

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C l O_{2}^{-}

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C l O_{4}^{-}

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Solution

The correct option is A $C l O^{-}$
$H C l O$ is the weakest acid, hence its conjugate base, i.e., $C l O^{-}$ is the strongest bronsted base.

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Similar questions

C l O^{-}

C l O_{2}^{-}

C l O_{3}^{-}

C l O_{4}^{-}

3 C l O^{-} \to C l O_{3}^{-} + 2 C l^{-}

C l O^{-} + C l O^{-} \to C l O_{2}^{-} + C l^{-} - - - - (s l o w)

C l O_{2}^{-} + C l O^{-} \to C l O_{3}^{-} + C l^{-} - - - - - (f a s t)

C l O^{-}, {C l O_{2}}^{-}, {C l O_{3}}^{-}, {C l O_{4}}^{-}

C l O^{-}, C l O_{2}^{-}, C l O_{3}^{-}

C l O_{4}^{-}

3 C l O^{-} ⟶ C l O_{2}^{-} + 2 {C l}^{-}

C l O^{-} + C l O^{-} K_{1} - \to C l O_{2}^{-} + {C l}^{-}

C l O_{2}^{-} + C l O^{-} K_{2} - \to C l O_{3}^{-} + {C l}^{-}

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