Which of the given pair of $S N_{1}$ reaction would you expect to proceed faster? Explain your answer.

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Solution

In both the compounds, a tertiary carbocation is formed so it depends on the tendency of leaving the group.
Quaternary ammonium salt:
It is a better leaving group so it will leave easily forming a carbocation.
On the other hand, $N (C H_{3})_{2}$ It is not a good leaving group.
Therefore it will proceed faster.

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