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Question

Which of the given statement is not true for glucose?


A

The pentacetate glucose does not react with hydroxylamine to give oxime

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B

Glucose reacts with hydroxylamine to form an oxime

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C

Glucose gives Schiff’s test for aldehyde

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D

Glucose exists in two crystalline forms alpha and beta

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Solution

The correct option is D

Glucose exists in two crystalline forms alpha and beta


Explanation for the correct option:

Glucose functions

Glucose's chemical equation ( C6H12O6). It's found in fruits and honey, and it's the most prevalent reason for large blood sugar in higher animals. Its metabolism must be carefully monitored because it is a major source of energy for overall cell activity.

Correct answer

Option(d) The fact that glucose occurs in two crystalline forms, alpha, and beta, is not true.

Explanation for the incorrect options:

Option(a)

Due to the obvious sheer aldehydic group, oxime is developed when D-glucose combines with hydroxylamine. D-glucose pentaacetate does not react with hydroxylamine since such aldehyde analysis was performed.

Option(b)

While glucose and hydroxylamine are used to manufacture oxime, cyanohydrin is generated without any need for hydrogen cyanide. In its open-chain structure, glucose has a carbonyl group.

Option(c)

Glucose seems to have an aldehyde group in its open structure, however, it also forms a cyclic acetal structure (also called pyranose). Despite the reality that it is a weak base, this system is focused and stable, and Schiff's reagent has no effect on it. It also fails Schiff's test since it does not release hydrazone.

Therefore, Option(d) There still are two crystalline forms of glucose: alpha and beta.


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