Which of the number given below should be multiplied to $232$ so that final number is divisible by $5$ ?

5

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10

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15

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None of the above.

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Solution

The correct option is C $15$
Multiplication of $232$ with any multiple of $5$ will make the final number divisible by $5$ because $5$ will always be the permanent factors of that number.

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Similar questions

{(5)}^{- 5}

(2^{32} + 1)

2^{- 5}

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