Which of the $O_{2}^{-}, O_{2}^{2 -}, C N^{-}$ and $N_{2}$ is/are paramagnetic ?

N_{2}

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O_{2}^{2 -}

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C N^{-}

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O_{2}^{-}

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Solution

The correct option is D $O_{2}^{-}$
Total number of electrons in $O_{2}^{-} = 17$

MOT electronic configuration of $O_{2}^{-} = K K, σ 2 s^{2}, σ^{} 2 s^{2}, σ 2 p_{z}^{2},$ $π 2 p_{x}^{2} \approx π 2 p_{y}^{2}, π^{} 2 p_{x}^{2} \approx π^{} 2 p_{y}^{1}$

One unpaired electron in anti-bonding $π^{} 2 p_{y}$ orbital indicates that $O_{2}^{-}$ ion is paramagnetic.

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Similar questions

$N_{2}$ and $O_{2}$ are converted into monocations, $N_{2}^{+}$ and $O_{2}^{+}$ respectively. Which of the following is wrong ?

N_{2}

O_{2}

N_{2}^{+}

O_{2}^{-}

C N^{-}, N O, O_{2}^{2 -}, O_{2}, N O_{2}, O_{2}^{-}, B_{2}, C_{2}, F_{2}^{-}

N_{2}

O_{2}

N_{2}^{-}

O_{2}^{-}

N O_{2} ⇌ \frac{1}{2} N_{2} + O_{2}, K_{1}

N_{2} O_{4} ⇌ 2 N O_{2}, K_{2}

N_{2} O_{4}

N_{2}

O_{2}

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