Which of the pair of complex compounds are tetrahedral as well as diamagnetic?

$[C o C l_{4}]^{-} a n d [C o (C O)_{4}]^{-}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$[A g (S C N)_{4}]^{2 -} a n d [N i C l_{4}]^{2 -}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$[C o (C O)_{4}]^{-} a n d [N i (C N)_{4}]^{4 -}$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$[P d C l_{4}]^{2 -} a n d [N i (C N)_{4}]^{2 -}$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C
$[C o (C O)_{4}]^{-} a n d [N i (C N)_{4}]^{4 -}$

Co in $[C o (C O)_{4}]^{-}$ :

Hybridization: $s p^{3}$ ,
$μ_{e f f} = 0$
$N i i n [N i (C N)_{4}]^{4 -}$ :

Hybridization: $s p^{3}$ ,
$μ_{e f f} = 0$

Suggest Corrections

Similar questions

[C o (N H_{3})_{5} (S C N)]^{2 +}

[N i C l_{4}]^{2 -}

[N i (C N)_{4}]^{2 -}

[N i (C N)_{4}]^{2 -}

{[N i {(C N)}_{4}]}_{4}^{2 -}

{[N i C l_{4}]}_{4}^{2 -}

N i (C O)_{4}, [N i (C N)_{4}]^{2 -}

N i C l_{4}^{2 -}

Explain on the basis of valence bond theory that [Ni(CN)₄]²⁻ ion with square

planar structure is diamagnetic and the [NiCl₄]²⁻ ion with tetrahedral geometry is paramagnetic.

Join BYJU'S Learning Program