Question

Which of the path (I) or (II) of a projectile has more time of flight? Use necessary assumptions.

• A. >
• B. <
• C. =
• D. Data insufficient

Answer 1

The correct option is C

=

Given $H_1$ = $H_2$
$\frac{u_{y_1}^2}{2g}$ = $\frac{u_{y_2}^2}{2g}$=$\frac{u_{y_1}^{2}si{n}^2{\theta }_1}{2g}$ $\Rightarrow$ $\frac{u_{y_2}^{2}si{n}^2{\theta }_2}{2g}$$\Rightarrow$$u_1$ sin ${\theta }_1$ = $u_2$ sin ${\theta }_2$ or $u_{y_1}$ = $u_{y_2}$
We know $T_1$ = $\frac{2u_{y_1}}{2}$$\frac{2u_{y_2}}{2}$ = $T_2$.
Hence both paths take the same time.