Question

Which of the points are points of trisection of A(2,-2) and B(-7,4)?

Answer 1

The points of trisection divides in the ratio (1,2) and (2,1). Applying the section formula

1st point of trisection, with ratio 1:2 = $(\frac{2\times -7+1\times 2}{1+2},\frac{2\times 4+1\times -2}{1+2})$ = $(-4,2)$

2nd point of trisection, with ratio 2:1 = $(\frac{1\times -7+2\times 2}{2+1},\frac{1\times 4+2\times -2}{2+1})$ = $(-1,0)$

Therefore the points of trisection are both (-4, 2) and (-1, 0).

Hence the points are (-4, 2) and (-1, 0).