Which of the possible compound will be formed in the following sequence of reaction?
$C H_{2} = C H_{2} H B r ⟶ X H y d r o l y s i s ⟶ Y N a_{2} C O_{3} ⟶ I_{2} e x c e s s Z :$

C_{2} H_{5} B r

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C_{2} H_{5} O H

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C H I_{3}

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C H_{3} C H O

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Solution

The correct options are
A $C_{2} H_{5} B r$
B $C_{2} H_{5} O H$
C $C H I_{3}$
$C_{2} H_{5} B r$ , $C_{2} H_{5} O H$ and $C H I_{3}$ will be formed in the following sequence of reaction. The reaction will be as follows:

$C H_{2} = C H_{2} H B r ⟶ C_{2} H_{5} B r X H y d r o l y s i s ⟶ C_{2} H_{5} O H Y N a_{2} C O_{3} ⟶ I_{2} e x c e s s C H I_{3} Z :$

A molecule of $H B r$ adds to the $C = C$ double bond of ethylene to form ethyl bromide. On hydrolysis, ethyl bromide gives ethyl alcohol. Ethyl alcohol undergoes haloform reaction to form iodoform.

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