Which of the reactants act as oxidant or reductant if any:

$2 C u S O_{4} + S O_{2} + 2 K B r + 2 H_{2} O \to 2 C u B r + 2 H_{2} S O_{4} + K_{2} S O_{4}$

C u S O_{4}

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S O_{2}

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Both of these

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None of these

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Solution

The correct option is C Both of these
The oxidation number of S (in $S O_{2}$ ) increases from +4 to +6 (in $K_{2} S O_{4}$ ). Thus, $S O_{2}$ is oxidized and acts as reductant.
The oxidation number of Cu (in $C u S O_{4}$ ) decreases from +2 to +1 (in $C u B r$ ). Thus, $C u S O_{4}$ is reduced and acts as oxidizing agent.

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Similar questions

What is the balanced form of the equation written below?

$C u + H_{2} S O_{4} \to C u S O_{4} + S O_{2} + H_{2} O$

2 C u^{2 +} + 4 I^{-} \to 2 C u I + I_{2}

C a + C l_{2} \to C a C l_{2}

2 I^{-} + H_{2} O_{2} \to 2 O H^{-} + I_{2}

C_{2} H_{4} + B r_{2} \to C_{2} H_{4} B r_{2}

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