Question

Which of the reactions would you choose for the most beneficial convertion shown below?
$Ar{N}_2^{+}\to ArCl$

• A. Sandmeyer Reaction
• B. Gattermann Reaction
• C. Directly reacting with HCl
• D. Both A and B

Answer 1

The correct option is A Sandmeyer Reaction

Sandmeyer and Gattermann reactions are two processes used mostly for the above convertion.

Sandmeyer reaction is a type of substitution reaction that is widely used in the production of aryl halides from aryl diazonium salts. Copper salts like chloride, bromide or iodide ions are used as catalysts in this reaction. Notably, Sandmeyer reaction can be used to perform unique transformations on benzene. The transformations include hydroxylation, trifluoromethylation, cyanation, and halogenation.

Gattermann reaction is used for obtaining chlorobenzene or bromobenzene from benzenediazonium chloride by treating it with Cu/HCl or Cu/HBr respectively.


But Sandmeyer is more beneficial as it gives a higher yield.

The reaction is as follows:

Hence, the correct answer is option (a).