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Standard XII

Chemistry

Electrolytes

Which of the ...

Question

Which of the reagents listed below could be added to water to make 0.1 M solution of $\oplus N H_{4}$ ions?
i. $N H_{3}$ ii. $N H_{4} C l$

N H_{3}

because it is a strong electrolyte

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N H_{4} C l

because it is a strong electrolyte

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N H_{3}

because it is a weak electrolyte

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N H_{4} C l

because it is a weak electrolyte

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Solution

The correct option is C $N H_{4} C l$ because it is a strong electrolyte
$N H_{4} C l$ , a strong electrolyte in water will give 0.1 M $\oplus N H_{4}$ ion to a solution. ( $N H_{3}$ , a weak electrolyte does not dissociate sufficiently to give 0.1 M $\oplus N H_{4}$ ions.)

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Similar questions

________ number reagents listed below could be added to water to make 0.1 M solution of

C l^{-}

ion?

N H_{3}

ii.

N H_{4} C l

iii.

C H_{3} C O O H

iv.

C H_{3} C O O N a

H C l

vi.

N a C l

Q. Assertion :An aqueous solution of

N H_{4} C l

changes blue litmus to red. Reason:

N H_{3}

is a weak base,

H C l

is a strong acid.

Q. Assertion :An aq. soln. of

N H_{3}

is a weak base and a weak electrolyte. Reason: Ammonia is a weak base and it combines with acids to form salts. With HCl it reacts to form ammonium chloride. 99.4% os ammonia molecules are protonated but does not completely ionize so it is a weak base and electrolyte.

Question 20.
In an attempt to demonstrate electrical conductivity through an electrolyte, the following apparatus ( see the figure ) was set up.

Which among the following statement(s) is/ are correct?
(i) Bulb will not glow because electrolyte is not acidic.
(ii) Bulb will glow because NaOH is a strong base and furnishes ions for conduction.
(iii) Bulb will not glow because circuit is incomplete.
(iv) Bulb will not glow because it depends upon the type of electrolytic solution.

(a) (i) and (iii)
(b) (ii) and (iv)
(c) (ii) only
(d) (iv) only

For weak electrolytes ˄m⁰ cannot to be calculated by extrapolation of ˄m⁰ vs (c)^1/2 graph. Which of the following is not the reason?

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Which of the reagents listed below could be added to water to make 0.1 M solution of ⊕NH4 ions?i. NH3 ii. NH4Cl

The correct option is C NH4Cl because it is a strong electrolyteNH4Cl, a strong electrolyte in water will give 0.1 M ⊕NH4 ion to a solution. (NH3, a weak electrolyte does not dissociate sufficiently to give 0.1 M ⊕NH4 ions.)

Which of the reagents listed below could be added to water to make 0.1 M solution of $\oplus N H_{4}$ ions?
i. $N H_{3}$ ii. $N H_{4} C l$

The correct option is C $N H_{4} C l$ because it is a strong electrolyte
$N H_{4} C l$ , a strong electrolyte in water will give 0.1 M $\oplus N H_{4}$ ion to a solution. ( $N H_{3}$ , a weak electrolyte does not dissociate sufficiently to give 0.1 M $\oplus N H_{4}$ ions.)