Which of the situation is represented by the velocity-time graph the shown in the diagram :

A stone thrown up vertically, returning back to the ground

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A car decelerating at constant rate and then accelerating at the same rate

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A ball falling from a height and then bouncing hack

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None of the above

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Solution

The correct options are
A A stone thrown up vertically, returning back to the ground
B A car decelerating at constant rate and then accelerating at the same rate

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Similar questions

Q. Three speed-time graphs are given below :

Figure

Which graph represents the case of :
(i) a cricket ball thrown vertically upwards and returning to the hands of the thrower?
(ii) a trolley decelerating to a constant speed and then accelerating uniformly?

Q. A ball is dropped vertically from a height

10 m

above the ground. It hits the ground and bounces up vertically to a height of

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. Neglecting subsequent motion and air resistance, which of the following options correctly represents the variation of its velocity

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with height

h

above the ground.

Three speed-time graphs are given below:
Which graph represents the case of:
(i) a cricket ball thrown vertically upwards and returning to the hands of the thrower?
(ii) a trolley decelerating to a constant speed and then accelerating uniformly?

Q. The figure shows velocity-time graph of a stone thrown vertically upwards till it comes back to the ground. Calculate the maximum height reached by the stone.

Q. A car accelerates from rest at a constant rate

α

for some time, after which it decelerates at a constant rate

β

and comes to rest. If the total time elapsed is t, then the maximum velocity acquired by car is

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Which of the situation is represented by the velocity-time graph the shown in the diagram :

The correct options are A A stone thrown up vertically, returning back to the ground B A car decelerating at constant rate and then accelerating at the same rate

The correct options are
A A stone thrown up vertically, returning back to the ground
B A car decelerating at constant rate and then accelerating at the same rate