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Torque

Which of the ...

Question

Which of the two forces acting on the rigid rod causes clockwise moment?

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Solution

Moment is given by $\to τ = \to r \times \to F$
The force $F_{2} = 12 g f$ causes clockwise moment and force $F_{1} = 20 g f$ causes anticlockwise moment.

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A half meter rod is pivoted at the centre with two weights of $20 g f$ and $12 g f$ suspended at a perpendicular distance of $6 c m$ and $10 c m$ from the pivot respectively as shown below.

i) Which of the two force acting on the rigid rod causes clockwise moment?

ii) is the rod in equilibrium?

Two forces $F_{1} = 5 N$ and $F_{2} = 8 N$ acting at points A and B on a rod pivoted at a point O, such that OA = $2 m$ and OB = $4 m$ . Calculate the total moment of the two forces about O.

State whether true or false.

At rotational equilibrium, the sum of clockwise moments equals the sum of anti-clockwise moments acting on a body.

F_{1}

F_{2}

act on a thin uniform elastic rod placed in space. Force

F_{1}

acts at right end of the rod and

F_{2}

acts exactly at centre of the rod as shown (both forces act parallel to length of the rod).

(i)

F_{1}

causes extension of rod while

F_{2}

causes compression of rod.

(i i)

F_{1}

causes extension of rod

F_{2}

also causes extension of rod.

(i i i)

F_{1}

causes extension of rod while

F_{2}

does not change length of rod.

The correct order of

T r u e / F a l s e

for above statements is

Q. An object is said to be in equilibrium when:
1. there is no net force acting on the object
2. the total clockwise moments about any point is equal to the total anti-clockwise moments about the same point
3. the object moves with constant velocity

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