Which of these cannot be the area of a right-angled triangle if the hypotenuse of the triangle is 13 m and one other side is 5 m?
Let the triangle be ABC where AC = 13 m and BC = 5 m
Using Pythagoras theorem we can write,
AB2=AC2−BC2
Therefore, AB2=132–52⇒AB=12 m
Area of triangle = 12×base×height=12×5×12=30 m2