Which of these compounds does not exist?

C u C l_{2}

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C u I_{2}

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C u F_{2}

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C u B r_{2}

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Solution

The correct option is D $C u I_{2}$
Since, $C u C l_{2}$ , $C u F_{2}$ , $C u B r_{2}$ are stable and they exist but $C u I_{2}$ not, because Iodide ions are strong reducing agents, Therefore, copper (II) Iodide reduces to insoluble copper (I) iodide. Thus $C u I_{2}$ is not stable, so it does not exist in solution.

Suggest Corrections

Similar questions

C u F_{2}, C u C l_{2}

C u B r_{2}

{C u S O}_{4}

\to

{C u I}_{2}

{C u I}_{2}

\to

{C u}_{2} I_{2}

I_{2}

I_{2}

{N a}_{2} S_{2} O_{3} \to

{N a}_{2} S_{4} O_{6}

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