Which of these does not represent a wave equation

y = A s i n (ω t - k x)

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y = A s i n (ω t + k x)

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y = A c o s (ω t - k x)

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y = A (ω t - k x)

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Solution

The correct option is D $y = A (ω t - k x)$
For a equation to be a wave equation, it should also be periodic. Adding a period T to any of the equations given above, will give back the same equation, except for the equation depicted in (d)
Thus , option (d) is the right answer

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Similar questions

Which of the following two wave equations can form stationary wave?

(i) $Y = A s i n (ω t - k x)$

(ii) $Y = A c o s (ω t - k x)$

(iii) $Y = A s i n (ω t + k x)$

(iv) $Y = A c o s (ω t + k x)$

y = A sin (ω t - k x)

y = A sin (ω t + k x)

y = a \sin (ω t - k x)

y = a \cos (ω t - k x)

\sqrt{2} a

y = a cos (ω t - k x)

x = 0

y = a s i n (ω t - k x)

y = a c o s (ω t - k x)

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