Which of these statements about $[C o (C N)_{6}]^{3 -}$ is true ?

[C o (C N)_{6}]^{3 -}

has no unpaired electrons and will be in a high-spin configuration.

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[C o (C N)_{6}]^{3 -}

has no unpaired electrons and will be in a low-spin configuration.

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[C o (C N)_{6}]^{3 -}

has four unpaired electrons and will be in a low-spin configuration.

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[C o (C N)_{6}]^{3 -}

has four unpaired electrons and will be in a high-spin configuration.

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Solution

The correct option is B $[C o (C N)_{6}]^{3 -}$ has no unpaired electrons and will be in a low-spin configuration.

$[C o (C N)_{6}]^{3 -}$ has no unpaired electrons and will have low spin configuration.

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