Question

Which one among the following pairs of ions cannot be separated by $H_{2}S$ in dilute hydrochloric acid ?

• A. $B{i}^{3+},S{n}^{4+}$
• B. $A{l}^{3+},H{g}^{2+}$
• C. $Z{n}^{2+},C{u}^{2+}$
• D. $N{i}^{2+},C{u}^{2+}$

Answer 1

Answer: (A)

$B{i}^{3+},S{n}^{4+}$

$B{i}^{3+}\left(IIA\right),S{n}^{4+}\left(IIB\right)$ cannot be separated by $H_{2}S$ in dilute hydrochloric acid. Both the radicals are precipitated as their sulphides $B{i}_2{S}_3\left(black\right)$ and $Sn{S}_2\left(yellow\right)$
Option A is correct.