Question

Which one has the highest cogulation power?

• A. $K^{+}$
• B. $C{a}^{++}$
• C. $A{l}^{+++}$
• D. $S{n}^{4+}$

Answer 1

Answer: (D)

$S{n}^{4+}$

The process of settling of colloidal particles is called coagulation.

The greater the valence of flocculating ion added the greater its power to cause precipitation. This is Hardy-Schulze rule. In the coagulation of negative solution the flocculating power is in order of:

$S{n}^{4+}>A{l}^{3+}>C{a}^{2+}>K^{+}$

Coagulating power $\propto \frac{1}{coagulatingvalue}$

The smaller the quantity needed the higher will be the coagulating power.