Which one has the highest paramagnetism?

N i (C O)_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[N i (N H_{3})_{4}] C l_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[N i (N H_{3})_{6}] C l_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

[C u (N H_{3})_{4}] C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $[N i (N H_{3})_{6}] C l_{2}$
The number of unpaired electrons in $N i (C O)_{4}$ , $[N i (N H_{3})_{4}] C l_{4}$ , $[N i (N H_{3})_{6}] C l_{2}$ and $[C u (N H_{3})_{4}] C l_{2}$ is 0, 0, 2 and 1 respectively. They undergo $s p^{3}$ , $d s p^{2}$ , $s p^{3} d^{2}$ and $d s p^{2}$ hybridization respectively.

Suggest Corrections

Similar questions

N i (C l_{4})^{2 -}, {[N i {(H_{2} O)}_{6}]}^{2 +}

[N i {(P {P h}_{3})}_{2} {C l}_{2}]

[N i {(C O)}_{4}]

{[N i {(C N)}_{4}]}^{2 -}

[C o (N H_{3})_{6}] C l_{3}

[N i (N H_{3})_{6}] C l_{2}

[C r (H_{2} O)_{6}] C l_{3}

[F e (H_{2} O)_{6}] C l_{2}

C l_{2}

C l_{4}

C l_{2}

C l 4

[N i (C O)_{4},, [N i C l_{4}]^{2 -}, [C o (N H_{2}), C l_{2}] C l, N a_{3} [C o F_{6}], N a_{2} O_{2} and C s O_{2} .]

\begin{matrix} Column - I & Column - II i . & [N i (C O)_{4}] & Planar octahedral, diamagnetic i i . & [F e (N O) (H_{2} O)_{5}]^{2 +} & Planar, paramagnetic i i i . & [C o (N O_{2})_{6}]^{3 -} & Octahedral, diamagnetic i v . & [C u (N H_{3})_{4}]^{2 +} & Planar octahedral, paramagnetic Octahedral, paramagnetic \end{matrix}

Join BYJU'S Learning Program