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Question

which one is correct regarding hemiacetal formation:

A
NaOH act as nucleophile for carbonyl
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B
NaOH increase electrophilicity of acetone.
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C
NaOH increase nucleophilicity of methanol.
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D
None of the above
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Solution

The correct option is C NaOH increase nucleophilicity of methanol.
Acidic proton of CH3OH is abstracted by NaOH which increases nucleophilicity of methanol and then by nucleophilic addition followed by protonation it forms hemiacetal.

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