Which one is the correct order of the size of the iodine species?

I > I^{+} > I^{-}

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I > I^{-} > I^{+}

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I^{+} > I^{-} > I

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I^{-} > I > I^{+}

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Solution

The correct option is D $I^{-} > I > I^{+}$
For a particular element, the order of the size of anion, cation and the neutral species is $a n i o n > e l e m e n t > c a t i o n$ . Cation has the smallest size due to greater z-effective. Size is inversely proportional to z-effective which is directly proportional to the positive charge.
Thus the size of $a n i o n > s i z e o f e l e m e n t > s i z e o f c a t i o n$

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Similar questions

Which of the following is the correct order of size of the given species
(a) $I > I^{-} > I^{+}$ (b) $I^{+} > I^{-} I$ (c) $I > I^{+} > I^{-}$ (d) $I^{-} > I > I^{+}$

Q. The size of the species

I, I^{-}

I^{+}

follows the order:

Q. The size of the species

I, I^{-}

I^{+}

follows the order:

The size of species $I$ , $I^{\oplus}$ and $I^{⊖}$ decreases in the order

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