Which one is the descending order of atomic radius of elements of third period?
$N a (z = 11), M g (z = 12), A l (z = 13)$ and $S i (z = 14)$

S i > A l > M g > N a

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N a > M g > A l > S i

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N a < M g < A l > S i

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N a > A l > M g = S i

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Solution

The correct option is B $N a > M g > A l > S i$
Redius $= N a > M g > A l > S i$
Moving through period $,$ atomic radii decreases due to more $Z_{e f f}$ across period from left to right $.$

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Similar questions

The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
(a) Na< Mg > Al < Si (b) Na> Mg > Al > Si
(c) Na< Mg< Al< Si (d) Na> Mg> Al < Si

Question 17
Arrange the following elements in the order of their decreasing metallic character
Na, Si, Cl, Mg, Al

(a) Cl > Si >Al > Mg >Na
(b) Na >Mg >Al >Si > Cl
(c) Na > Al > Mg > Cl > Si
(d) Al > Na> Si > Ca> Mg

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

Q. The first ionisation energies of six

3^{r d}

period elements are 496, 578, 738, 789, 1000 and 1012

{kJ mol}^{- 1}

. The elements to which these energies correspond respectively are:

N a^{+}

M g^{2 +}

A l^{3 +}

and

S i^{4 +}

are isoelectronic, their ionic size will follow the order:

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Which one is the descending order of atomic radius of elements of third period?Na(z=11),Mg(z=12),Al(z=13) and Si(z=14)

The correct option is B Na>Mg>Al>SiRedius=Na>Mg>Al>SiMoving through period, atomic radii decreases due to more Zeff across period from left to right.

Which one is the descending order of atomic radius of elements of third period?
$N a (z = 11), M g (z = 12), A l (z = 13)$ and $S i (z = 14)$

The correct option is B $N a > M g > A l > S i$
Redius $= N a > M g > A l > S i$
Moving through period $,$ atomic radii decreases due to more $Z_{e f f}$ across period from left to right $.$