Question

Which one is the most likely structure of $CrC{l}_3.6H_{2}O$ if 1 / 3 of total chlorine of the compound is precipitated by adding $AgN{O}_3$ to its aqueous solution :

• A. $CrC{l}_3.6H_{2}O$
• B. $\left[CrC{l}_3{\left(H_{2}O\right)}_3\right].{\left(H_{2}O\right)}_3$
• C. $\left[CrC{l}_2{\left(H_{2}O\right)}_4\right].Cl.2H_{2}O$
• D. $\left[CrCl{\left(H_{2}O\right)}_5\right].C{l}_2.H_{2}O$

Answer 1

Answer: (C)

$\left[CrC{l}_2{\left(H_{2}O\right)}_4\right].Cl.2H_{2}O$

As 1 / 3 of total chlorine of the compound is precipitated by adding $AgN{O}_3$ to its aqueous solution so only one chloride ion is available for ionization, so compound is $\left[CrC{l}_2\right(H_{2}O{)}_4]Cl.2H_{2}O$.