Question

Which one of $3^{X^7}$ and $3^{y^4}$ is more stable? Give reason.

Answer 1

${}_3{X}^7$ Nucleus :

Number of protons $p=3$

Number of neutrons $n=7-3=4$

Neutron to proton ratio $\frac{n}{p}=\frac{4}{3}$

${}_3{Y}^4$ Nucleus :

Number of protons $p=3$

Number of neutrons $n=4-3=1$

Neutron to proton ratio $\frac{n}{p}=\frac{1}{3}$

Neutron to proton ratio is more in ${}_3{X}^7$, so it is more stable.