The correct option is
C OCl−(A) In
Cr2O72−, the oxidation state of
Cr is
+6, which is maximum oxidation of
Cr. It can only lower down its oxidation state. So, it acts only as an oxidising agent.
(B) In
NO3−, the oxidation state of
N is
+5, which is the maximum oxidation of
N. It can only lower its oxidation state and so, it acts only as an oxidising agent.
(C) In
OCl−, the oxidation state of
Cl is
+1 and
Cl shows oxidation state from
−1 to
+7 and so, it can undergo both oxidation and reduction.
(D) In
S2−, the oxidation state of
S is
−2, which is the minimum oxidation state of
S and so, it can only increase its oxidation state and hence, it acts only as a reducing agent.
Therefore, OCl− can undergo both oxidation as well as reduction.