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Question
Which one of the following arrangement represents the correct order of electron gain enthalpy (with negative sign) of given atomic species?
Which one of the following arrangement represents the correct order of electron gain enthalpy (with negative sign) of given atomic species?
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Solution
The correct option is B Cl<F<S<O
In chlorine and fluorine. Cl has high electron gain enthalpy because the small size of F and there is very high electronic repulsion among the electrons of fluorine. This makes incoming of another electron not very favourable.In sulphur and oxygen, sulphur has high electron gain enthalpy than oxygen because of larger size and lower electron density.So, O<S<F<ClThe Cl has a most negative electron gain enthalpy and O has a least negative electron gain enthalpy.By considering the negative sign, the more negative value will be small and less negative value will be large.Thus, the correct order will be Cl<F<S<O
In chlorine and fluorine. Cl has high electron gain enthalpy because the small size of F and there is very high electronic repulsion among the electrons of fluorine. This makes incoming of another electron not very favourable.
In sulphur and oxygen, sulphur has high electron gain enthalpy than oxygen because of larger size and lower electron density.
So, O<S<F<Cl
The Cl has a most negative electron gain enthalpy and O has a least negative electron gain enthalpy.
By considering the negative sign, the more negative value will be small and less negative value will be large.
Thus, the correct order will be Cl<F<S<O
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