Question

Which one of the following can't be the square of natural number?

• A. $1936$
• B. $2452$
• C. $1369$
• D. $6561$

Answer 1

The correct option is B $2452$

As we know that all the perfect square number ends with $1,4,9,6,5,00$

$2452$ is not a perfect square because it ends in 2.

$\text{Also}1936=(44{)}^{2}1369=(37{)}^{2}6561=(81{)}^2$