Question

Which one of the following compound can exhibit geometrical isomer?

• A. butanal
• B. butanol
• C. but-2-ene
• D. but-2-yne

Answer 1

The correct option is C but-2-ene

Condition to show geometrical isomerism : $XYC=CXY$
X and Y must have different groups/atoms attached to carbon on the same side of double bond.
Among given compounds, only but-2-ene shows geometrical isomerism.
Other two do not have double bonds; therefore, they can not show geometrical isomerism.