The correct option is C 2,2,3,3-Tetramethylbutane
Option A will give 4 mono brominated products, as Br can go on C1/C2/C3/C4 and all are different.
Option B compound name is wrong.
Option C will give 1 mono brominated products, as Br can go on C1/C4 and both are symmetric.
Option D will give 2 mono brominated products, as Br can go on C1/C2/C3 but C1 and C3 are symmetric.