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Question

Which one of the following compounds show geometrical isomerism?

A
1,1-dibromoprop-1-ene
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B
propene
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C
2-methylprop-1-ene
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D
1,2-dibromobut-2-ene
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Solution

The correct option is D 1,2-dibromobut-2-ene
Conditions for geometrical isomers:
1) Free rotation must be restricted.
2) Both the terminals must be attached with different groups.
3) Terminals must not be in perpendicular planes.
a has two same groups(Br) attached to the terminal carbon of the double bond so it can't show geometrical isomerism.

b has two same groups (H) attached to the terminal carbon of the double bond so it can't show geometrical isomerism.

c has two same groups (H) attached to the terminal carbon of the double bond so it can't show geometrical isomerism.

d has two different groups attached to the terminal carbons of the double bond so it will show geometrical isomerism

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