Which one of the following constitutes a group of the isoelectronic species?

C N^{-}, N_{2}, O_{2}^{2 -}, C_{2}^{2 -}

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N_{2}, O_{2}^{-}, N O^{+}, C O

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C_{2}^{2 -}, O_{2}^{-}, C O, N O

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N O^{+}, C_{2}^{2 -}, C N^{-}, N_{2}

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Solution

The correct option is D $N O^{+}, C_{2}^{2 -}, C N^{-}, N_{2}$
Isoelectronic species possess same number of electrons. $N O^{+}, C_{2}^{2 -}, C N^{-}$ and $N_{2}$ , each have 14 electrons and thus are isoelectronic.

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Similar questions

Q. There are some species given below.

(i) O_{2}^{+} (i i) C O (i i i) B_{2} (i v) O_{2}^{-}

(v) N O^{+} (v i) H e_{2}^{+} (v i i) C_{2}^{2 +} (v i i i) C N^{-}

(i x) N_{2}^{-}

Total number of species which have their fractional bond order.

Q. Select, isoelectronic species out of the following:

C O,

N O^{+},

O_{2}^{-},

C H_{4},

C N^{-},

N O

Calculate the total number of molecules that will possess fractional bond order among the following molecules
$O_{2}^{2 +}, N_{2}^{2 +}, O_{2}^{+}, N O, C O, C O^{+}, O_{2}^{-}, N O^{2 +}, C N^{-}, N O^{2 -}, N_{2}^{-}$

Among the following the total no. of species which are paramagnetic

$O_{2}, S_{2}, C N^{-}, N O^{+}, O_{2}^{2 +}, O_{2}^{2 -}, B_{2}, N_{2}^{2 -}, O_{2}^{+}, N O, N O_{2}, N_{2} O$ ___

Q. How many species are dimagnetic and have their bond order greater than 2.5?

N_{2}, N_{2}^{\oplus}, N O^{\oplus}, N O^{⊖}, C O, C N^{⊖}, K O_{2}, N a_{2} O_{2}

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Which one of the following constitutes a group of the isoelectronic species?

The correct option is D NO+, C2−2, CN−, N2Isoelectronic species possess same number of electrons. NO+, C2−2, CN− and N2, each have 14 electrons and thus are isoelectronic.

The correct option is D $N O^{+}, C_{2}^{2 -}, C N^{-}, N_{2}$
Isoelectronic species possess same number of electrons. $N O^{+}, C_{2}^{2 -}, C N^{-}$ and $N_{2}$ , each have 14 electrons and thus are isoelectronic.