Which one of the following electrolytes has the same value of van't Hoff factor $(i)$ as that of $K_{4} F e (C N)_{6}$ (if all are 100% ionised)?

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Solution

$K_{4} [F e (C N)_{6}]$ dissociates as:
$K_{4} [F e (C N)_{6}] S o l^{n} ⟶ 4 K^{+} + 1 [F e (C N)_{6}]^{- 4}$
Van't Hoff factor:
$i = 5$
Option (a):
$A l_{2} (S O_{4})_{3} S o l^{n} ⟶ 2 A l^{+ 3} + 3 S O_{4}^{- 2}$
Van't Hoff factor :
$i = 5$

Option (b) :
$N a C l S o l^{n} ⟶ N a^{+} + C l^{-}$
Van't Hoff factor :
$i = 2$
Option (c) :
$A l (N O_{3})_{3} S o l^{n} ⟶ 1 A l^{+ 3} + 3 N O_{3}^{-}$
Van't Hoff factor :
$i = 4$
Option (d) :
$N a_{2} S O_{4} S o l^{n} ⟶ 2 N a^{+} + 1 S O_{4}^{2 -}$
Van't Hoff factor :
$i = 3$
Only option (a) i.e. $A l_{2} (S O_{4})_{3}$ has the same value of Van't Hoff factor as that of $K_{4} F e (C N)_{6}$
Option (a) is correct.

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A l_{2} (S O_{4})_{3}

(i)

K_{4} F e (C N)_{6}

(i)

A l_{2} (S O_{4})_{3}

100 %

Which one of the following electyrolytes has the same value of van’t Hoff factor (i) as that of $A l_{2} (S O_{4})_{3}$ (if all are 100% ionized)?

K_{4} F e (C N)_{6}

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