Which one of the following elements exhibits the maximum number of valence electrons?
(Atomic numbers: $N a - 11, A l - 13, S i - 14, P - 15$ )

N a

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A l

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S i

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P

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Solution

The correct option is B $P$
Let us take a look at the electronic configuration of the given elements.
$N a -$ $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{1}$
$A l -$ $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{1}$
$S i -$ $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{2}$
$P -$ $1 s^{2}, 2 s^{2}, 2 p^{6}, 3 s^{2}, 3 p^{3}$
Thus, phosphorus has the maximum number of valence electrons, i.e., 5.

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Which one of the following elements exhibits the maximum number of valence electrons?(Atomic numbers: Na−11,Al−13,Si−14,P−15)

The correct option is B PLet us take a look at the electronic configuration of the given elements. Na− 1s2,2s2,2p6,3s1Al− 1s2,2s2,2p6,3s2,3p1Si− 1s2,2s2,2p6,3s2,3p2P− 1s2,2s2,2p6,3s2,3p3Thus, phosphorus has the maximum number of valence electrons, i.e., 5.

Which one of the following elements exhibits the maximum number of valence electrons?
(Atomic numbers: $N a - 11, A l - 13, S i - 14, P - 15$ )