Which one of the following elements has the highest number of unpaired electrons?

_{25} M n

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_{24} C r

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_{96} C m

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_{26} F e

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Solution

The correct option is C $_{96} C m$
The electronic configuration of the given elements is as:

$_{25} M n = [A r] 3 d^{5} 4 s^{2} (5$ unpaired electrons)

$_{24} C r = [A r] 3 d^{5} 4 s^{1} (6$ unpaired electrons)

$_{96} C m = [R n] 5 f^{7} 6 d^{1}, 7 s^{2} (8$ unpaired electrons)

$_{26} F e = [A r] 3 d^{6} 4 s^{2} (4$ unpaired electrons)

Thus, $_{96} C m$ has the highest number of unpaired electrons.

Hence, option $C$ is correct.

Suggest Corrections

	Column I (Atom)		Column II (No. of unpaired electrons)
(A)	$_{15} P$	(i)	6 unpaired electrons
(B)	$_{24} C r$	(ii)	2 unpaired electrons
(C)	$_{26} F e$	(iii)	3 unpaired electrons
(D)	$_{14} S i$	(iv)	4 unpaired electrons