Which one of the following has a potential more than zero?

P t, \frac{1}{2} H_{2} (1 a t m) | H C l (1 M)

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P t, \frac{1}{2} H_{2} (1 a t m) | H C l (2 M)

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P t, \frac{1}{2} H_{2} (1 a t m) | H C l (0.1 M)

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P t, \frac{1}{2} H_{2} (1 a t m) | H C l (0.5 M)

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Solution

The correct option is B $P t, \frac{1}{2} H_{2} (1 a t m) | H C l (2 M)$
$P t, \frac{1}{2} H_{2} (1 a t m) | H C l (2 M)$ has a potential more than zero.
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} l o g \frac{1}{[H^{+}]} = 0 - \frac{0.0592}{1} l o g \frac{1}{2} = 0.0178 V$

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Similar questions

Q. An electrochemical cell is set up as

P t, H_{2} (1 a t m) | H C l (0.1 M) | | {C H}_{3} C O O H (0.1 M) | H_{2} (1 a t m), P t

The emf of the cell is not zero because:

P t (H_{2}) (p_{1}) | H C l (0.1 M) | (C l_{2}) (p_{2})

Pt cell reaction will be endergonic if:

Q. For the cell Pt |

H_{2}

(0.4 atm) |

H^{+}

(pH = 1) || (pH = 2) |

H_{2}

90.1 atm) | Pt. The measured potential at

25^{\circ} C

is:

[PT = length of tangent, $(x_{1}, y_{1})$ is the point where the tangent is drawn, is the angle the tangent makes with x-axis, $x_{1}, y_{1}$ , PT > 0]

How many of the following gives the length of subtangent ?

Which of the following gives the length of subtangent ?

[PT = length of tangent, (x1,y1) is the point where the tangent is drawn, $θ$ is the angle the tangent makes with x-axis, x1, y1, PT > 0]

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Which one of the following has a potential more than zero?

The correct option is B Pt,12H2(1atm)|HCl(2M)Pt,12H2(1atm)|HCl(2M) has a potential more than zero.Ecell=E0cell−0.0592nlog1[H+]=0−0.05921log12=0.0178V

The correct option is B $P t, \frac{1}{2} H_{2} (1 a t m) | H C l (2 M)$
$P t, \frac{1}{2} H_{2} (1 a t m) | H C l (2 M)$ has a potential more than zero.
$E_{c e l l} = E_{c e l l}^{0} - \frac{0.0592}{n} l o g \frac{1}{[H^{+}]} = 0 - \frac{0.0592}{1} l o g \frac{1}{2} = 0.0178 V$