Question

Which one of the following has highest number of stereoisomers?

• A. $\left[Ru\right(N{H}_3{)}_{4}Cl2{]}^{+}$
• B. $\left[Co\right(N{H}_3{)}_{5}Cl{]}^{2+}$
• C. $\left[Ir\right(P{R}_3{)}_{2}H\left(CO\right){]}^{2+}$
• D. $\left[Co\right(en{)}_{2}C{l}_2{]}^{+}$

Answer 1

The correct option is D $\left[Co\right(en{)}_{2}C{l}_2{]}^{+}$

A) It has two geometrical isomers i.e., cis and trans form and no option isomer is possible in
this case.
B) No geometrical or optical isomer is shown by this compound.
C) It has two geometrical isomers i.e., cis and trans form and no optical isomer is possible in the
case.
D) It has two geometric (cis and trans form) and two optical isomers. The optical isomerism is
possible for cis form only.