Which one of the following has maximum number of atoms of oxygen?

2 g

H_{2} O

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2 g

{S O}_{2}

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2 g

{C O}_{2}

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2 g

C O

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Solution

The correct option is B $2 g$ of $H_{2} O$
Number of atoms present in 2g of $H_{2} O$ is $= \frac{6.023 \times 10^{23}}{18} = 0.335 \times 10^{23} \times 2 = 0.67 \times 10^{23}$

Number of atoms present in 2g of ${S O}_{2}$ is $= \frac{6.023 \times 10^{23}}{64} = 0.094 \times 10^{23} \times 2 = 0.188 \times 10^{23}$
Number of atoms present in 2g of ${C O}_{2}$ is $= \frac{6.023 \times 10^{23}}{44} = 0.136 \times 10^{23} \times 2 = 0.272 \times 10^{23}$
Number of atoms present in 2g of $C O$ is $= \frac{6.023 \times 10^{23}}{28} = 0.215 \times 10^{23} \times 2 = 0.43 \times 10^{23}$
So the maximum number of atoms of oxygen is present in $H_{2} O$ .
Option A is correct.

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