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Question

Which one of the following has the regular tetrahedral structure?

A
BF4
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B
SF4
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C
XeF4
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D
[Ni(CN)4]2
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Solution

The correct option is A BF4
Boron has sp3 hybridisation with 4 bond pairs and no lone pairs. BF4 has regular tetrahedral geometry. SF4 has sp3d hybridization. XeF4 has sp3d2 hybridization. [Ni(CN)4]2 is dsp2 hybridized.
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