Which one of the following have the highest oxidation number for chlorine?

H C l O_{2}

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K C l O_{3}

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H C l

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K C l O_{4}

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C a C l_{2}

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Solution

The correct option is D $K C l O_{4}$
The oxidation number of $C l$ in the given compounds is as shown below.
$H C l O_{2}$ +3
$K C l O_{3}$ +5
$H C l$ -1
$K C l O_{4}$ +7
$C a C l_{2}$ -1
Thus, the highest oxidation number of chlorine is in $K C l O_{4}$

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Similar questions

H C l O_{4}, H O C l, C l F_{3}, H C l O_{3}

Arrange the following compounds according to the increasing order of oxidation state of chlorine.

$H C l O_{4}, H C l O_{3}, H C l O_{2}, H C l O$

C a + {C l}_{2} ⟶ {C a C l}_{2}

K C l O_{4}

K C l O_{4}

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