Which one of the following hydroxide is insoluble in water?

C a (O H)_{2}

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B a (O H)_{2}

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B e (O H)_{2}

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M g (O H)_{2}

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Solution

The correct option is B $B e (O H)_{2}$
In hydroxides of alkaline earth metals, hydration energy does not alter very much while lattice energy decreases down the group due to increase in size.
The overall effects of the two factor is that $△ H$ solution of the hydroxides
$(△ H s o l u t i o n = △ H_{l a t t i c e} - △ H_{h y d r a t i o n})$
becomes more negative from Be to Ba and hence solubility increases from top to bottom.
$B e (O H)_{2} < M g (O H)_{2} < C a (O H)_{2} < S r (O H)_{2} < B a (O H)_{2}$
Hence, $B e (O H)_{2}$ is the least soluble in water.

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Similar questions

B a (O H)_{2} > S r (O H)_{2} > C a (O H)_{2} > B e (O H)_{2}

M g (O H)_{2}

M g (O H)_{2}

B e (O H)_{2}, M g (O H)_{2}, A l (O H)_{2}, L i O H, B (O H)_{3}, Z n (O H)_{2}

H_{2} O ?

(1) B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

(2) B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

(3) L i O H < N a O H < K O H < R b O H

(4) L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

H_{2} O

B e S O_{4} > M g S O_{4} > C a S O_{4} > B a S O_{4}

B e (O H)_{2} > M g (O H)_{2} > C a (O H)_{2} > B a (O H)_{2}

L i O H < N a O H < K O H < R b O H

L i_{2} C O_{3} < N a_{2} C O_{3} < K_{2} C O_{3} < R b_{2} C O_{3}

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