Which one of the following ions exhibit highest magnetic moment?

C u^{2 +}

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T i^{3 +}

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N i^{2 +}

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M n^{2 +}

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Solution

The correct option is D $M n^{2 +}$
As magnetic moment is $\sqrt{n (n + 2)}$ where n is no. of unpair electron.
$T i^{+ 3} 3 d^{1}$ configuration has 1 unpair electron
$N i^{+ 2} 3 d^{8}$ configuration has 2 unpair electron
$M n^{+ 2} 3 d^{5}$ configuration has 5 unpair electron
$C u^{+ 2} 3 d^{9}$ configuration has 1 unpair electron
so highest magnetic moment will be for $M n^{+ 5} 3 d^{5}$ configuration

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Similar questions

T i^{3 +}, C u^{+}, N i^{2 +}, F e^{3 +}, M n^{2 +}, C o^{2 +}

M^{2 +}

Z n^{2 +} > S c^{2 +} = C u^{2 +} > T i^{2 +} = N i^{2 +} > V^{2 +} = C o^{2 +} > C r^{2 +} = F e^{2 +} > M n^{2 +}

Magnetic moment of which ion is 2.88 BM ?

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