CrO2−4 Electronic configuration Cr6+=[Ar]
Unpaired electron (n) = 0; hence diamagnetic.
Hence, there is no d-d transition and no paramagnetism.
Cr2O2−7 Electronic configuration Cr6+=[Ar]
Unpaired electron (n) =0; hence diamagnetic.
Hence, there is no d-d transition and no paramagnetism. Its colour is due to charge transfer spectra.
MnO2−4 Electronic configuration Mn6+=[Ar]3d1
Unpaired elctron (n) = 1; hence paramagnetic
Unpaired elctron gives rise to d-d transition and paramagnetism.
MnO−4 Electronic configuration Mn7+=[Ar]
Unpaired electron (n) =0; hence diamagnetic
Hence, there is no d-d transition and no paramagnetism. Its colour is due to charge transfer spectra.
Option (c) is correct